solution of the problem no. 6
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Answer:
4000 Rs.
Step-by-step explanation:
Let the price of one chair be 'x' and one table be 'y'.
Given,
Price of 3 chairs and 2 tables = 4500 Rs
⇒ 3x + 2y = 4500
Multiplying by 3 both side,
⇒ 9x + 6y = 13500
⇒ 6y = 13500 - 9x eq.[1]
Price of 5 chairs and 3 tables = 7000 Rs
⇒ 5x + 3y = 7000
Multiplying by eq.[2] both side,
⇒ 10x + 6y = 14000
⇒ 10x + 13500 - 9x = 14000 eq.[From 1]
⇒ x = 500
Putting this in eq.[1]
⇒ 6y = 13500 - 9(500)
⇒ 6y = 13500- 4500
⇒ 6y = 9000
⇒ y = 1500
Also, Price of 2 chairs and 2 tables = 2x + 2y
= 2(500) + 2(1500)
= 1000 + 3000 = 4000 Rs.
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