Question

) Solution of the quadratic inequality x2+x+1≤0 is​

Answer 1

Answer:

First, find the 2 x-intercepts (real roots) by solving

f

(

x

)

=

x

2

+

x

+

1

=

0

.

D = d^2 = b^2 - 4ac = 1 - 4 = -3.

There is no x-intercepts. Since a > 0, the parabola opens upward and is completely above the x-axis.

The inequality f(x) > 0 is always true, regardless of x.

graph{x^2 + x + 1 [-10, 10, -5, 5]}