Solution of the reduce equation y"-y'-2y=0
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The thing about differential equations is that you need boundary conditions if you want a quantifiable solution. A differential equation without boundary conditions of some sort can have infinite solutions. For this equation, y=0 works fine. But if you have a boundary condition like y’=1 when y=0, then y”=1. Then y(s)=1s and y’(s) = 1+-s and y’ is solvable (where s is some tiny increment). We can continue this forever and numerical simulate the result, but the result will be different depending on the starting point.
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