Math, asked by abinayasri4400, 9 months ago

Solution of the system of linear equations 3x - 2y = 0, 2x + y = 7 is

Answers

Answered by ahanatarafder06
2

Answer:

3x - 2y = 0

= 3x = 2y

= x =  \frac{2}{3} y

2x + y = 7

= 2( \frac{2}{3} y) + y = 7

= \frac{4y}{3}  + y = 7

= \frac{4y + 3y}{3}  = 7

= 7y = 7 \times 3

= y =  \frac{21}{7}

y = 3

x =  \frac{2}{3} y =  \frac{2}{3}  \times 3 = 2

So, \: x = 2 \: and \: y = 3

Answered by zaibunn00
1

Answer:

x= 2

y= 3

Step-by-step explanation:

3x-2y=0

-2y= -3x

y= -3x/-2

y= 3x/2

Put the value of y in equation two

2x+y= 7

2x+3x/2=7

4x+3x/2=7

7x/2=7

x=7×2/7

x=2

Now find the value of y using equation one

3x-2y=0

3×2-2y=0

6-2y=0

-2y= -6

y= -6/-2

y= 3

You can check your answer

3×2-2×3=0

6-6=0

Equation satisfied

Answer is correct

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