Question

Solution of this...​

Answer 1

Answer:

D2 = 3D1

Solutions

For first 10 seconds

S = ut+1/2at^2

Initial car is at rest so distance traveled is S =50aV = u+at = 10a

This final velocity is initial velocity for next ten seconds

S = 10at+1/2at^2

=100a+50a = 150a

So D2= 3D1

Answer 2

Answer:

this answer is right.....