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Given 4α/(α² +1) ≥ 1
=> 4 / (α + 1/α) ≥ 1
Let α + 1/α = 2 n + 1 as it is an odd integer.. n is some integer.
=> 4 / (2n+1) ≥ 1
=> 2n+1 ≤ 4
=> n ≤ 3/2
If n is negative the inequality is not valid. n can be 0 and 1.
So there are two possible values of n. There are two possible values of α + 1/α which are 1 and 3.
=> α² - α + 1 = 0 and α² - 3 α + 1 = 0
=> α is imaginary . α = [3 + √5] /2
So α has two real values. If imaginary values can be also taken into account, then α has four values.
=> 4 / (α + 1/α) ≥ 1
Let α + 1/α = 2 n + 1 as it is an odd integer.. n is some integer.
=> 4 / (2n+1) ≥ 1
=> 2n+1 ≤ 4
=> n ≤ 3/2
If n is negative the inequality is not valid. n can be 0 and 1.
So there are two possible values of n. There are two possible values of α + 1/α which are 1 and 3.
=> α² - α + 1 = 0 and α² - 3 α + 1 = 0
=> α is imaginary . α = [3 + √5] /2
So α has two real values. If imaginary values can be also taken into account, then α has four values.
kvnmurty:
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