Question

Solution of (x - 1)2(x + 1)3 (x-4) >O is​

Answer 1

−1<x<4

Given, (x1)

2

(x+1)

3

(x4)<0

Since square of a number cannot be <0

This means, one of (x+1)

3

or (x4) is <0

Now, (x+1)

3

<0 and x−4>0 => x<−1 and x>4 --- (1)

OR (x+1)

3

>0 and x−4<0 => x>−1 and x<4 --- (2)

From solutions of both possibilities, −1<x<4

hope you understand

Answer 2

Answer:

(x-1)2(x+1)3(x-4)>Ois

=

-1<x<4