solution of x+1 is divided by remainder
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For finding the remainder, we need to use remainder theorom
let p(x)=x
31
+31
x6−2x5+3x2+4
x3−2x2+x+1
Hence, to find the remainder on dividing p(x) by x+1, we need to equate x+1 to 0 and put that value of x in p(x).
x+1=0
∴x=−1
p(−1)=(−1)
31
+31=30
Thus x
31
+31 leaves remainder 30 when divided by x+1
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