Question

solution of x^2p+y^2q=z^2 by langrange's partial differential equation​

Answer 1

Step-by-step explanation:

Form the PDE by eliminating the arbitrary constants a and b from z = (x + a)(y + b). x + a = q and y + b = p Substituting in (1), we get z = pq. Example 1.4. Form the PDE by eliminating a, b from u = (x2 +a2)(y2 + b2).