Solution pf (7e+4f)^2 with the help of algebric identity
Answers
Answer:
The algebraic equations which are valid for all values of variables in them are called algebraic identities. They are also used for the factorization of polynomials. In this way, algebraic identities are used in the computation of algebraic expressions and solving different polynomials. You have already learned about a few of them in the junior grades. In this article, we will recall them and introduce you to some more standard algebraic identities, along with examples.
Algebraic Identities
Standard Algebraic Identities List
All the standard Algebraic Identities are derived from the Binomial Theorem, which is given as:
latex \mathbf{a+b^{n} =\; ^{n}C_{0}.a^{n}.b^{0} +^{n} C_{1} . a^{n-1} . b^{1} + …….. + ^{n}C_{n-1}.a^{1}.b^{n-1} + ^{n}C_{n}.a^{0}.b^{n}}/latex
Some Standard Algebraic Identities list are given below:
Identity I: a + b2 = a2 + 2ab + b2
Identity II: a – b2 = a2 – 2ab + b2
Identity III: a2 – b2= a + ba – b
Identity IV: x + ax + b = x2 + a + b x + ab
Identity V: a + b + c2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Identity VI: a + b3 = a3 + b3 + 3ab a + b
Identity VII: a – b3 = a3 – b3 – 3ab a – b
Identity VIII: a3 + b3 + c3 – 3abc = a + b + c(a2 + b2 + c2 – ab – bc – ca)
Example 1: Find the product of x + 1x + 1 using standard algebraic identities.
Solution: x + 1x + 1 can be written as x + 12. Thus, it is of the form Identity I where a = x and b = 1. So we have,
x + 12 = x2 + 2x1 + 12 = x2 + 2x + 1
Example 2: Factorise (x4 – 1) using standard algebraic identities.
Solution: (x4 – 1) is of the form Identity III where a = x2 and b = 1. So we have,
(x4 – 1) = ((x2)2– 12) = (x2 + 1)(x2 – 1)
The factor (x2 – 1) can be further factorised using the same Identity III where a = x and b = 1. So,
(x4 – 1) = (x2 + 1)(x2 –12) = (x2 + 1)x + 1x – 1
Eample 3: Factorise 16x2 + 4y2 + 9z2 – 16xy + 12yz – 24zx using standard algebraic identities.
Solution: 16x2 + 4y2 + 9z2– 16xy + 12yz – 24zx is of the form Identity V. So we have,
16x2 + 4y2 + 9z2 – 16xy + 12yz – 24zx = 4x2 + -2y2 + -3z2 + 24x-2y + 2-2y-3z + 2-3z4x= 4x – 2y – 3z2 = 4x – 2y – 3z4x – 2y – 3z
Example 4: Expand 3x – 4y3 using standard algebraic identities.
Solution: 3x– 4y3 is of the form Identity VII where a = 3x and b = 4y. So we have,
3x – 4y3 = 3x3 – 4y3– 33x4y3x – 4y = 27x3 – 64y3 – 108x2y + 144xy2
Example 5: Factorize (x3 + 8y3 + 27z3 – 18xyz) using standard algebraic identities.
Solution: (x3 + 8y3 + 27z3 – 18xyz)is of the form Identity VIII where a = x, b = 2y and c = 3z. So we have,
(x3 + 8y3 + 27z3 – 18xyz) = x3 + 2y3 + 3z3 – 3x2y3z= x + 2y + 3z(x2 + 4y2 + 9z2 – 2xy – 6yz – 3zx)
To learn more about algebraic identities, download BYJU’S The Learning App.
1,45,616
Frequently Asked Questions on Algebraic Identities
What are the three algebraic identities in Maths?
The three algebraic identities in Maths are:
Identity 1: a+b^2 = a^2 + b^2 + 2ab
Identity 2: a-b^2 = a^2 + b^2 – 2ab
Identity 3: a^2 – b^2 = a+b a-b
What is the difference between an algebraic expression and identities?
An algebraic expression is an expression which consists of variables and constants. In expressions, a variable can take any value. Thus, the expression value can change if the variable values are changed. But algebraic identity is equality which is true for all the values of the variables.
How to verify algebraic identity?
The algebraic identities are verified using the substitution method. In this method, substitute the values for the variables and perform the arithmetic operation. Another method to verify the algebraic identity is the activity method. In this method, you would need a prerequisite knowledge of Geometry and some materials are needed to prove the identity.
Quiz on Algebraic Identities
Quiz Image
Put your understanding of this concept to test by answering a few MCQs. Click ‘Start Quiz’ to begin!
Select the correct answer and click on the “Finish” button
Check your score and answers at the end of the quiz