solution please.
a^8+9=a^4/b^2(10b^2-b^4-4).
then find the value of a^12+b^10=?
Ans is. 59
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I don't know mujhe pta hota to btati
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Ans. 59
Step-by-step explanation:
Concept usedused is (X-1/X)²=X²+(1/X²)-2
So, a⁴+(9/a⁴)=10-b²-(4/b²)
a⁴₊3²/a⁴-10+b²+4/b²-4=0
(a²)²-6+(3²/a⁴) + b²-4+(2²/b²)=0
(a²-3/a²)² + (b-2/b)² =0
we know if x²+y²=0
x=0
y=0
therefore,
(a²-3/a²) =0, a⁴=3, (a⁴)³=a¹²=3³=27------------(1)
(b-2/b) =0, b²=2, (b²)⁵=b¹⁰=2⁵=32--------------(2)
On adding 1 and 2 we get
27+32=59
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