Question

solution please.

a^8+9=a^4/b^2(10b^2-b^4-4).
then find the value of a^12+b^10=?

Ans is. 59​

Answer 1

Answer:

I don't know mujhe pta hota to btati

Answer 2

Answer:

Ans. 59

Step-by-step explanation:

Concept usedused is (X-1/X)²=X²+(1/X²)-2

So, a⁴+(9/a⁴)=10-b²-(4/b²)

a⁴₊3²/a⁴-10+b²+4/b²-4=0

(a²)²-6+(3²/a⁴)   +   b²-4+(2²/b²)=0

(a²-3/a²)²     +     (b-2/b)² =0

we know if x²+y²=0

x=0

y=0

therefore,

(a²-3/a²) =0, a⁴=3, (a⁴)³=a¹²=3³=27------------(1)

(b-2/b) =0, b²=2, (b²)⁵=b¹⁰=2⁵=32--------------(2)

On adding 1 and 2 we get

27+32=59