Question

solution please don't ignore​

Answer 1

Answer:

• Now, see in triangle ACP»
• CR = r = AR (radius of the larger circle)
• Now, we can also write,
• From the figure, we can say CD = r, DB = rl
• To find AS, we need to apply Pythagora's theorem in triangle ABQ.
• Therefore, in triangle ABQ,
• AQ = BQ = rl (radius of the smaller circles)
• Therefore, AB = v/9r1
• Therefore, AB = r + rl(l + v")
• Applying Pythagoras theorem in triangle ACR,
• 2r2 = (r -F rl(1 -F
• r = rl(3 + 20)
• Now, sum of areas of 4 smaller circles = 41rr 2
• And, the area of the larger circle = Irr
• Therefore, the ratio of areas =
• 4Tr12
• 17 + 2v'2
• Using equation (1), we get the ratio of areas=4