Question

solution please I will mark it brainlliest

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

It is just the combination of 2 concepts: area of traingle and similarity.

Step-by-step explanation:

Area of triangle ADB= base x height /2 = DB x AN /2 = DB x AN x 0.5

Area of triangle CDB= DB x CM /2 = DB x CM x 0.5

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Therefore, Area(ADB)÷Area(CDB)=

(DB x AN x 0.5)/ (DB x CM x 0.5)

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Area(ADB)÷Area(CDB)= AN/CM ---------- ( i )

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Now, in triangles ANO and CMO,

AN || CM (since both perpendicular to same side)

side NO || MO (collinear)

AO || CO (collinear)

angle ANO = angle CMO = 90 degrees.

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So, triangle ANO ~ triangle CMO (similar triangles S-A-S).

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Thus, by property of similarity of triangles,

AN/ CM = AO/ CO. ------------- ( ii )

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From ( i ) and ( ii ), we get,

Area(ADB)÷Area(CDB) = AO/ CO = AN/ CM.