Math, asked by namballabhavana23, 11 days ago

solution pleses
anybody

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Answered by sheetalsharmass63923
0

 \frac{ \sqrt{11 + 6 \sqrt{2} } }{ \sqrt{17 - 2 \sqrt{72} } }   -  \sqrt{22 - 4 \sqrt{18} }  = a + b \sqrt{2}

simplify

 \frac{ \sqrt{2 }  + 3}{3 - 2 \sqrt{2} }  - (3 \sqrt{2}  - 2)

subtract b.√2 from both side

a + b \sqrt{2}  - b \sqrt{2 }  =  \frac{ \sqrt{2} + 3 }{3 - 2 \sqrt{2} }  - 3 \sqrt{2}  - 2 - b \sqrt{2}

a=9√2+13-3√2+2-√2b

a= -√2b+6√2+15

a=15

b√2=6√2

b=6

(a+b)=(15+6)

ANSWER= 21

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