Question

Solution pls...... ​

Answer 1

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✍W =5v°/3l

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EXPLANATION —

↪Actually u doesn't provided options which should be mentioned as θ = 37°

↪I m taking θ =37° for easy calculation

Velocity component along AB = 0

∴v°cos θ = v sin θ ⇒v = v°cot θ

at θ = 37°, v = 4/3 v°

$\huge w = \frac{Relative\: velocity\: perpendicular\: to\: AB}{l}$

⇒$\huge w = \frac{v°sinθ+vcosθ}{l}$

⇒$w = \frac{v° \: \frac{3}{5} \: + \frac{4}{3v°} \times \frac{4}{5} }{l}$

⇒$w = \frac{5v°}{3l}$

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