Question

solution pls...
trigonometry class 10​

Answer 1

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$\longrightarrow \sf\sin \theta = \sqrt{3} \cos\theta \\ \\ \longrightarrow \sf \frac{ \sin\theta}{ \cos\theta} = \sqrt{3} \\ \\\longrightarrow \sf \tan\theta = \sqrt{3} \\ \\ \longrightarrow \sf\tan\theta = \tan60 \degree \\ \\ \longrightarrow \sf \theta = 60 \degree$

Therefore

$\longrightarrow \sf\sin \theta = \sin60 \degree = \frac{ \sqrt{3} }{2} \\ \\ \longrightarrow \sf\cos \theta = \cos60 \degree = \frac{1}{2}$

Answer 2

Answer:

hope it helps uh. . . . . . . . . . .