Question

solution plzzz only q4
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Answer 1

$\bold \red \star \: \large\underline{Given:-}$

$Quadratic \: Equation:- \\ \\ \: \: \: \: \: \: \: \: \: 2 {x}^{2} - 4x + 3 = 0.$

$Comparing \: with \: \red {general }\: \: equation$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold { a {x}^{2} + bx + c = 0. }\\ \\ \: where \: as , \\ \: \: \\ \: \: \: \: \dot \: \: \bold {a = 2} \: \: \: \: \: \bold {b = - 4 }\: \: \: \: and \: \: \: \: \bold{c = 3. }$

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$\\ Now, \\ \: \: \: \: \: \: \: \: \: \: Discriminant = \bold{{ {b}^{2} - 4ac.}}$

$\bold D= {b}^{2} - 4ac. \\ \\ \: \: \: \: \: = {(- 4) }^{2} - 4(2)(3) . \\ \\ \: \: \: \: \: = 16 - 24. \\ \\ \: \: \: \: \: = - 8.$

Here we can see,

$\bold{D < 0.}$

The nature of roots become negative or

we can say,

$\bold{ Nature \: of \: Roots} \longrightarrow\\ \\ \: \: \: \: \: \: \: \bold { ( Roots \: are \: not \: real. )}$