Question

'solution set of inequation 7x-5/8x+3>4'.

Answer 1

$\Large{\mathfrak{\underline{\underline{Answer :-}}}}$

INEQUALITIES

Given function -

$\sf \dfrac{7x - 5}{8x + 3} > 4$

$\sf \dfrac{7x - 5}{8x + 3} - 4 > 0$

$\sf \dfrac{7x - 5 - 4 ( 8x + 3 )}{8x + 3} > 0$

$\sf \dfrac{- 25 x - 17}{8x + 3} > 0$

Now furthermore solving for general range :

x ∈ ( - 17/ 25 , - 3/8 )