Solution set of the inequality 3≥x is: *
(-∞,3)
(3,∞)
(-∞,3]
[3,∞)
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Solutions set of the inequality: 3^x (0.333...)^(x + 3)< (19)^x is
Using 0.33... = 13 , we can write the inequality as 3^x (13)^x + 3<3^-2x = 3^-3<3^-2x - 3< - 2x x< 32 or x∈ ( - ∞, 32 ] Ans: B
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