Solution set of x^2 + √2x-4=0 is
Answers
Answered by
0
Answer:
The equation can be easily solved by factoring
x
2
−
2
x
−
4
which is done by applying the quadratic formula.
δ
=
b
2
−
4
a
c
=
(
−
2
)
2
−
4
(
1
)
(
−
4
)
=
4
+
16
=
20
x
1
=
−
b
+
√
δ
2
a
=
2
+
√
20
2
=
2
+
√
4
⋅
5
2
=
2
+
2
√
5
2
x
1
=
(
1
+
√
5
)
x
2
=
−
b
−
√
δ
2
a
=
2
−
√
20
2
=
2
−
√
4
⋅
5
2
=
2
−
2
√
5
2
x
2
=
(
1
−
√
5
)
x
2
−
2
x
−
4
=
0
⇒
(
x
−
x
1
)
(
x
−
x
2
)
=
0
⇒
(
x
−
(
1
+
√
5
)
)
(
x
−
(
1
−
√
5
)
)
=
0
⇒
x
−
(
1
+
√
5
)
=
0
⇒
x
=
1
+
√
5
OR
x
−
(
1
−
√
5
)
=
0
⇒
x
=
1
−
√
5
Answered by
0
Step-by-step explanation:
⇒ The given quadratic equation is x
2
−2x−4=0, comparing it with ax
2
+bx+c=0
⇒ We get, a=1,b=−2 and c=−4
⇒ D=b
2
−4ac
=(−2)
2
−4(1)(−4)
=4+16
=20
∴ Discriminant of the given quadratic equation is 20.
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