Question

solution this problem

Answer 1

$hey \: mate \: \\ here \: is \: your \: answer \\ \\ \frac{1 - {x}^{2} }{x(1 - 2x)} = \frac{1 - {x}^{2} }{ x - {2x}^{2} } \\ \\ 2) \: \frac{2}{(1 - x)(1 + {x}^{2}) } = \\ \frac{2}{1(1 + {x}^{2} ) - x(1 + x ^{2} )} = \\ \frac{2}{1 + {x}^{2} - x - {x}^{3} } = \\ \frac{2}{ - x ^{3} + x ^{2} - x + 1 }\\ =\:-\frac{2}{x^3+x^2-x+1}$