Question

Solution to problem no. 3
3 cos (x) + 2sin(x) = 0

plz give answer in full​

Answer 1

Answer:

X=2nπ±2π/3

Step-by-step explanation:

sin²X=1-cos²X

So, the equation changes to 3cosX+2(1-cos²x)=0

2cos²X-3cosX-2=0

2cos²X-4cosX+cosX-2=0

2cosX(cosX-2)+1(cosX-2)=0

(2cosX+1)(cosX-2)=0

cosX≠2

2cosX+1=0

2cosX=-1

cosX=-1/2

X=2nπ±2π/3