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solution to the above question ...!!!
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a resistance of parallel series= 1\R1 + 1 \ R2
=1\10 + 1\40
on solving.........the resistance is 1\8
therefore resistance is 8ohm...
resistance in parallel on the bottom of the series
= 1\30+1\20+1\60
on solving
= 1\10
therefore equivalent resistance is = 10 ohm + 8 ohm= 18 ohm.................1
b V = 1.8 V
R = 18 ohm
according to ohm's law
V=IR
I =V\R
1.8\18 = 0.1 ampere....
HOPE IT HELPS!!!!!!!..............
lekshmisantosh2003:
did you understand it ????
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