Math, asked by mtejas495, 11 months ago

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Answered by kvnmurty
31

Answer:

Both triangles ABC and DEC are similar triangles.

Step-by-step explanation:

In the quadrilateral ABED,  m(∠B) = 75°.

     Given  m(∠EDC) = 75°,

     So m(∠ADE) = 180 ° - m(∠EDC) = 180° - 75° = 105°.

    So m(∠ADE) + m(∠ABE) = 180°.

    So m(∠A ) + m(∠BED) = 360° - 180° = 180°

    Since m(∠BED) + m(∠DEC) = 180°,  m(∠DEC) = m(∠A).

Compare the two triangles now:

    m(∠A) = m(∠DEC)

    m(∠DCE) = m(∠ACB)

     m (∠EDC) = m(∠ABC) =  75°

Since the measures of the three angles match in both triangles, they are similar triangles.

Answered by shahasatyam
3

Answer:

both triangle are similar

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