Question

Solution to this problem?

Answer 1

in triangle ABC
AC^2 = AB^2+BC^2
AC^2 = 2764+2764( AS SQUARE OF 42 IS 2764)
SO AC= 74.35cm
AREA OF TRIANGLE ABC= 1/2*BASE *HEIGHT
AREA = 1/2*42*42= 882CM^2
AS AC IS THE DIAMETER OF THE semicircle THAN ITS AREA = pie*R^2*1/2
SO AREA = 22/7. * 74.35/2. *74.35/2*1/2
AREA OF SEMICIRCLE IS = 2671.68cm^2
SO area of figure is =
area of triangle+ area of semicircle
area of figure= (882+2671.68)cm^2
area= 3553.68




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