Question

Solutions for the equation 5x + 7y=50

Answer 1

Given, equation

• 5x+7y=50------(2)

let

• 5x=50-7y
• X=50-7y/5----(1)

putting the value of X in equation 1

$= > 5x = \frac{50 - 7y}{5} \\ \\ = > 5 \times ( \frac{50 - 7y}{5} ) = \frac{50 - 7y}{5} \\ \\ = > 250 - 35y = 50 - 7y \\ \\ = > - 7y + 35y = 250 - 50 \\ \\ = > 28y = 200 \\ \\ = > y = \frac{50}{7}$

Again putting the value of of y in equation 2

$= > 5x + 7y = 50 \\ \\ = > 5x + 7 \times \frac{50}{7} = 50 \\ \\ = > 5x + 50 = 50 \\ \\ = > 5x = 50 - 50 \\ \\ = > x = 0$

Verification

$5x + 7y = 50 \\ \\ 5 \times 0 + 7 \times \frac{50}{7} = 50 \\ \\ 0 + 50 = 50 \\ \\ 50 = 50$

Hence, proved