Math, asked by kushal5971, 7 months ago

solutions of ex.4.1 9th

Answers

Answered by ffddfgggfd
7

Answer:

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Step-by-step explanation:

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Answered by Anonymous
8

Answer:

The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.

(Take the cost of a notebook to be ₹ x and that of a pen to be ₹ y)

Solution:

Let the cost of a notebook to be = ₹ x

Let the cost of a pen to be = ₹ y

According to the question,

The cost of a notebook is twice the cost of a pen.

i.e., Cost of a notebook = 2 Cost of a pen

x = 2 y

x = 2y

x-2y = 0

x-2y= 0 is the linear equation in two variables to represent the statement ‘The cost of a notebook is twice the cost of a pen’.

2. Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:

(i)2x + 3y = 9.3\overline{5}

5

Solution:

2x + 3y = 9.3\overline{5}

5

Re-arranging the equation, we get,

2x + 3y – 9.3\overline{5}

5

= 0

The equation 2x + 3y – 9.3\overline{5}

5

= 0 can be written as,

2x + 3y + (- 9.3\overline{5}

5

) = 0

Now comparing 2x + 3y + (-9.3\overline{5}

5

) = 0 with ax + by + c = 0

We get,

a = 2

b = 3

c = – 9.3\overline{5}

5

(ii) x – y/5 – 10 = 0

ncert solutions for class 9 maths chapter 4 fig 1

(iii) –2x + 3y = 6

Solution:

–2x + 3y = 6

Re-arranging the equation, we get,

–2x + 3y – 6 = 0

The equation –2x + 3y – 6 = 0 can be written as,

(–2)x + 3y +(– 6) = 0

Now comparing (–2)x + 3y +(– 6) = 0 with ax + by + c = 0

We get, a = –2

b = 3

c = -6

(iv) x = 3y

ncert solutions for class 9 maths chapter 4 fig 2

(v) 2x = –5y

Solution:

2x = –5y

Re-arranging the equation, we get,

2x + 5y = 0

The equation 2x + 5y = 0 can be written as,

2x + 5y + 0= 0

Now comparing 2x + 5y + 0= 0 with ax + by + c = 0

We get, a = 2

b = 5

c =0

(vi) 3x + 2 = 0

Solution:

3x + 2 = 0

The equation 3x + 2 = 0 can be written as,

3x + 0y + 2 = 0

Now comparing 3x +0 + 2= 0 with ax + by + c = 0

We get, a = 3

b = 0

c =2

(vii) y – 2 = 0

Solution:

y – 2 = 0

The equation y – 2 = 0 can be written as,

0x + 1y + (–2) = 0

Now comparing 0x + 1y + (–2) = 0with ax + by + c = 0

We get, a = 0

b = 1

c = –2

(viii) 5 = 2x

Solution:

5 = 2x

Re-arranging the equation, we get,

2x = 5

i.e., 2x– 5 = 0

The equation 2x– 5 = 0 can be written as,

2x + 0y – 5 = 0

Now comparing 2x + 0y – 5 = 0 with ax + by + c = 0

We get, a = 2

b = 0

c =5

Step-by-step explanation:

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