Solutions of the equation ax+by+c=0 and a2x+b2y+c2=0 are consistent then the current form is
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Answer:
Decomposition of KClO
3
is given by,
2KClO
3
△
2KCl+3O
2
2mole2moles3moles
1.491g0.672
1 mole of O
2
occupies 22.4dm
3
of O
2
Then 0.672dm
3
of O
2
=
22.4
0.672
=0.03 moles.
1 mole of O
2
=32g.
∴0.03 moles of O
2
=32×0.03=0.96g
∴ Mass of potassium chlorate =M(KCl)+M(O
2
)
=1.491+0.96
=2.451g
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