Question

Solutions of the equation y=px +log p

Answer 1

Given the differential equation, y=px+p2.

Now differentiating both sides with respect to x we get,

p=p+(x+2p)dxdp

or, dxdp=0 or, 2p+x=0.

Now,

dxdp=0 gives general solution.

or, p=c [ On integrating we've]

So the general solution is y=cx+c2.