Question

Solv 7/2x+2+13/y+2=27and 13/2x+1+7/y+2=33

Answer 1

Ans.

$\frac{7}{2x + 1} + \frac{13}{y + 2} = 27 .....(1)\\ \frac{13}{2x + 1} + \frac{7}{y + 2} = 33.....(2)$

We multiply (1) by 13 and (2) by 7. We get
$\frac{91}{2x + 1} + \frac{169}{y + 2} = 351.....(3) \\ \frac{91}{2x + 1} + \frac{49}{y + 2} = 231.....(4)$

Subtracting (3) and (4), we get
$\frac{120}{y + 2} = 120 \\ or \: \: y + 2 = 1 \\ or \: \: y = - 1$
From (1), we get
$x = - \frac{1}{4}$

Hence the required solution is
$x = - \frac{1}{4} \: \: and \: \: y = - 1$

I HOPE THAT THIS HELPS YOU.