Math, asked by gopalbhavsar411, 1 day ago

solv the following equation by matrix method.2x+3y-z=-3,5x+y+3z=10,4x+3y-2z=-3​

Answers

Answered by 25levin2005
0

Answer:

Step-by-step explanation:

Solution

verified

Verified by Toppr

Given system of linear equations are  

2x+3y+3z=5

x−2y+z=−4

3x−y−2z=3.

Represent it in matrix form

 

2

1

3

 

3

−2

−1

 

3

1

−2

 

 

 

x

y

z

 

=  

 

5

−4

3

 

 which is in the form of AX=B

A=  

 

2

1

3

 

3

−2

−1

 

3

1

−2

 

 

∣A∣=10+15+15=40

=0

∴ A  

−1

 exists

To find adjoint of A

A  

11

=5,A  

12

=5,A  

13

=5

A  

21

=3,A  

22

=−13,A  

23

=11

A  

31

=9,A  

32

=1,A  

33

=−7

Adj(A)=co-factor  

 

5

3

9

 

5

−13

1

 

5

11

−7

 

 

             =  

 

5

5

5

 

3

−13

11

 

9

1

−7

 

 

A  

−1

=  

∣A∣

1

Adj(A)

            =  

40

1

 

 

5

5

5

 

3

−13

11

 

9

1

−7

 

 

X=A  

−1

B

   =  

40

1

 

 

5

5

5

 

3

−13

11

 

9

1

−7

 

 

 

5

−4

3

 

   

X=  

40

1

 

 

25−12+27

25+52+3

25−44−21

 

 

X=  

40

1

 

 

40

80

−40

 

 

 

x

y

z

 

=  

 

1

2

−1

 

 

Hence, x=1,y=2 and z=−1Solution

verified

Verified by Toppr

Given system of linear equations are  

2x+3y+3z=5

x−2y+z=−4

3x−y−2z=3.

Represent it in matrix form

 

2

1

3

 

3

−2

−1

 

3

1

−2

 

 

 

x

y

z

 

=  

 

5

−4

3

 

 which is in the form of AX=B

A=  

 

2

1

3

 

3

−2

−1

 

3

1

−2

 

 

∣A∣=10+15+15=40

=0

∴ A  

−1

 exists

To find adjoint of A

A  

11

=5,A  

12

=5,A  

13

=5

A  

21

=3,A  

22

=−13,A  

23

=11

A  

31

=9,A  

32

=1,A  

33

=−7

Adj(A)=co-factor  

 

5

3

9

 

5

−13

1

 

5

11

−7

 

 

             =  

 

5

5

5

 

3

−13

11

 

9

1

−7

 

 

A  

−1

=  

∣A∣

1

Adj(A)

            =  

40

1

 

 

5

5

5

 

3

−13

11

 

9

1

−7

 

 

X=A  

−1

B

   =  

40

1

 

 

5

5

5

 

3

−13

11

 

9

1

−7

 

 

 

5

−4

3

 

   

X=  

40

1

 

 

25−12+27

25+52+3

25−44−21

 

 

X=  

40

1

 

 

40

80

−40

 

 

 

x

y

z

 

=  

 

1

2

−1

 

 

Hence, x=1,y=2 and z=−1

Answered by harmipatel2244
0

Answer:

hope you understand.. and plz.. chaek the all the documents carefully

Attachments:
Similar questions