Question

solv this question (2a-3b-c)²

Answer 1

Hey friend,
Here is the answer you were looking for:
${(2a - 3b - c)}^{2} \\ \\ using \: the \: identity : \\ (a - b -c)^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab + 2bc - 2ac \\ \\ (putting \: the \: values) \\ \\ = {(2a)}^{2} + {(3b)}^{2} + {(c)}^{2} - 2(2a)(3b) + 2(3b)(c) - 2(2a)(c) \\ \\ = 4 {a}^{2} + {9b}^{2} + {c}^{2} - 12ab + 6bc - 4ac$

Hope this helps!!

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@Mahak24

Thanks...
☺☺

Answer 2

Hey!!!! your answer is here!!!!
4a²-12ab-4ac+9b²+6bc+c².

hey I'm sorry.. I'm not giving full explain.