Question

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Answer 1

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↬Let sin –¹ 3/5 = a and sin _¹ 8/17

↬Let sin _¹ 3/5 = a

↬sin a = 3/5

↬cos a = √1 - sin² a

= √1 - (3/5)²

= √1 -9/2 = 4/5

↬cos a = 4/5

↬Let sin -¹ 8/17 = b

↬sin b = 8/17

↬cos b = √1 -sin² b

= √1 - (8/17)²

=√1 - 64/289 = 15/17

cos B = 15/17

↬we know that :-

↬cos (a - b) = 4/5 × 15/17 + 3/5 × 8/17

↬cos ( a - b) = 60+24/17x5

↬cos (a-b) = 84/85

↬cos (a - b) = cos -¹ (84/85)

↬: sin -¹ 3/5 - sin - ¹ 8/7 = cos -¹ [84/85 ]

Answer 2

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