Question

solve = 0=20+4 (m-6) by L.H.S and R.H.S

Answer 1

Solution :

0 = 20+4(m-6)

Subtract 20 both sides of the equation,

we get

=> -20 = -20 + 20 + 4(m-6)

=> -20 = 4(m-6)

Divide each term by 4 , we get

=> ( -20/4 ) = [4(m-6)]/4

=> -5 = m - 6

Add 6 both sides of the equation, we get

=> -5 + 6 = m - 6 + 6

=> 1 = m

Therefore ,

m = 1

•••••

=>

Answer 2

$\textbf{\huge{ANSWER:}}$

Given:

20 + 4( m - 6 ) = 0

Multiply by 4, as given;

=》 20 + 4m - 24 = 0

=》 4m - 4 = 0

=》 4m = 4

4 is common, therefore, we can cancel it, leaving only 1 on the R.H.S.;

=》 m = 1

Now, as we've got the value, let's check it;

= 20 + 4( 1 - 6 )

= 20 + 4 - 24

= 4 - 4

= 0

L.H.S. = R.H.S.

$\tt{Hence Proved!}$