Math, asked by sohan33350, 11 months ago

Solve 0.2x + 0.3y = 2.1;0.4x + 0.5y = 3.7 by substitution method.

Answers

Answered by rishu6845

Ans---> x = 3 and y = 5

Given---> 0.2x + 0.3y = 2.1

0.4x + 0.5y = 3.7

To find ---> Value of x and y .

Solution--->

0.2x + 0.3y = 2.1

Multiplying whole equation by 10, we get

=> 10 × 0.2x + 10 × 0.3y = 10 × 2.1

=> 2x + 3y = 21

=> 2x = 21 - 3y

=> x = (21 - 3y) / 2 -------------(1)

Now taking second equation,

0.4x + 0.5y = 3.7

Multiplying whole equation by 10 , we get,

=> 10 × 0.4x + 10 × 0.5y = 10 × 3.7

=> 4x + 5y = 37

Putting x = ( 21 - 3y ) / 2 in it , we get,

=> 4 ×( 21 - 3y ) / 2 + 5y = 37

=> 2 ( 21 -3y ) + 5y = 37

=> 42 - 6y + 5y = 37

=> - y = 37 - 42

=> - y = - 5

=> y = 5

Now putting y = 25 in (1), we get

=> x = ( 21 - 3y ) / 2

= { 21 - 3 ( 5 ) } / 2

= (21 - 15 ) / 2

= ( 6 / 2 )

x = 3

Answered by Aɾꜱɦ

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