Solve, 0.4 + 0.3 = 1.7; 0.7 − 0.2 = 0.8
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4
Answer:
Your question is incopmlete bro
But i found u r question and here is u r answer
Step-by-step explanation:
Q- 0.4x+0.3y=1.7;0.7x-0.2y=0.8
Answer
First of all multiply both equations by 10 to get 4x+3y=17(eq 1)
and
7x-2y=8(eq 2)
We will solve this question by substitution method
From eq 2 7x-2y=8
Transporting values
7x=8+2y
x=(8+2y)/7
Therefore we get x=8+2y/7
Now we will substitute value of x in eq1
4(8+2y/7)+3y=17
32+8y/7+3y=17
32+8y+21y/7=17..(taking LCM=7)
32+29y=17.7
29y=119-32
29y=87
y=3
Now substitute value of y in eq2 to get
7x-2(3)=8
7x-6=8
7x=8+6
x=2
I hope it will help u
And dont forget to give thanks and mark me as brainlist❤ ꈍᴗꈍ
Answered by
3
Answer:
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