Math, asked by mchowdhary577, 11 days ago

Solve 0.4x + 0.3y = 1.7 and 0.7x - 0.2y = 0.8 by cross multiplication method​

Answers

Answered by Anonymous
2

Answer:

Answer: x=2,y=3.

Step-by-step explanation:

0.4x+0.3y=1.7, 0.7x-0.2y=0.8. multiply both by 10 to get 4x+3y=17--- 1. and 7x-2y=8---2. so,from 2, x=8+2y/7. substitute value of y in 1 to get. 4(8+2y/7)+3y=17.

32+8y/7+3y=17. 32+8y+21y/7=17. 32+29y=17.7. 29y=119-32. 29y=87.

y=3. substitute value of y in eq2 to get. 7x-2(3)=8. 7x-6=8. 7x=8+6.

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