Question

solve 0.4x+0.5y=2.2 and 0.5x-0.2y=1.1​

Answer 1

Answer:

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Answer 2

Answer:

x=3,y=2

Step-by-step explanation:

  0.4x+0.5y=2.2

+ 0.5x-0.2y=1.1

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  0.9x+0.3y=3.3 => 9x+3y=33=>3(3x+y)=3(11) => 3x+y=11

0.4x+0.5y=2.2 => x=(2.2-0.5y)/0.4=> ((22-5y)/4)/(10/10) => (22-5y)/4

substitue in 3x+y=11

3((22-5y)/4)+y=11

(66-15y)/4 + y=11

66/4 -15y/4 + 4y/4 = 44/4

(66-15y+4y)/4= 44/4

66-15y+4y=44

66-44 = 15y-4y

22 = 11y

y=2

substitute in x=(22-5y)/4

x=22-5(2)/4

x=(22-10)/4

x=12/4

x=3