Math, asked by ushanatarajan7636, 16 days ago

solve 1/2(2x+3y)+12/7(3x-2y)=1/2​

Answers

Answered by rinkusinha824
0

Step-by-step explanation:

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Answered by masterrrrrkhan123
0

Answer:

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1 Simplify \frac{1}{2}(2x+3y)

2

1

(2x+3y) to \frac{2x+3y}{2}

2

2x+3y

.

\frac{2x+3y}{2}+\frac{12}{7}(3x-2y)=\frac{1}{2}

2

2x+3y

+

7

12

(3x−2y)=

2

1

2 Simplify \frac{12}{7}(3x-2y)

7

12

(3x−2y) to \frac{12(3x-2y)}{7}

7

12(3x−2y)

.

\frac{2x+3y}{2}+\frac{12(3x-2y)}{7}=\frac{1}{2}

2

2x+3y

+

7

12(3x−2y)

=

2

1

3 Multiply both sides by 1414 (the LCM of 2, 72,7).

7(2x+3y)+24(3x-2y)=7

7(2x+3y)+24(3x−2y)=7

4 Expand.

14x+21y+72x-48y=7

14x+21y+72x−48y=7

5 Simplify 14x+21y+72x-48y14x+21y+72x−48y to 86x-27y86x−27y.

86x-27y=7

Divide both sides by 8686.

x=\frac{7+27y}{86}

x=

86

7+27y

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