Question

Solve (1+2iota) whole cube

Answer 1

Step-by-step explanation:

${(1 + 2i)}^{3} \\ = {(1)}^{3} + {(2i)}^{3} + 3(1)(2i)(1 + 2i) \\ = 1 + 8 {i}^{3} + 6i(1 + 2i) \\ = 1 + 8i {i}^{2} + 6i + 12 {i}^{2} \\ = 1 - 8i + 6i - 12 \\ = - 2i - 11$

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