solve, 1 /3a+b+3x = 1/ 3a + 1 /b +1 /3x
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in this question
first we take similar terms in one side
1/3a+ b+ 3x = 1/3a+ 1/b + 1/3x
1/3a + b + 3x - 1/3a - 1/b -1/3x = 0
1/3a is cancel with 1/3a and we break b and 3x in equal parts means b= 1/b and 1/b , 3x = 1/ 3x and 1/3x .
the remaining is
1/b + 1/b - 1/b +1/3x +1/3x - 1/3x = 0
1 / b is cross with - 1/b and 1/3x is also cross with -1/3x
the remaining is 1/b + 1/3x it is answer of this question
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