Math, asked by parmodkumar7009, 6 months ago

solve, 1 /3a+b+3x = 1/ 3a + 1 /b +1 /3x​

Answers

Answered by Anugodara
6

Answer:

in this question

first we take similar terms in one side

1/3a+ b+ 3x = 1/3a+ 1/b + 1/3x

1/3a + b + 3x - 1/3a - 1/b -1/3x = 0

1/3a is cancel with 1/3a and we break b and 3x in equal parts means b= 1/b and 1/b , 3x = 1/ 3x and 1/3x .

the remaining is

1/b + 1/b - 1/b +1/3x +1/3x - 1/3x = 0

1 / b is cross with - 1/b and 1/3x is also cross with -1/3x

the remaining is 1/b + 1/3x it is answer of this question

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