Solve: 1/(3x-2) +1/(x-3) =1
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Step-by-step explanation:
1/(3x - 2) + 1/(x - 3) = 1
Taking LCM,
x - 3 + 3x - 2/(3x^2 - 11x + 6) = 1
4x - 5 = 3x^2 - 11x + 6
3x^2 - 15x + 11 = 0
By using Sridharacharya,
a = 3, b = -15, c = 11
x = [-b +- under root (b^2 - 4ac)]/2a
x = [15 +- under root (-15^2 - 4 × 3 × 11)]/2 × 3
x = [15 +- under root (225 - 132)]/6
x = [15 +- under root(93)]/6
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