Math, asked by ridhman15, 11 months ago

Solve: 1/(3x-2) +1/(x-3) =1

Answers

Answered by vedansh074
1

Step-by-step explanation:

1/(3x - 2) + 1/(x - 3) = 1

Taking LCM,

x - 3 + 3x - 2/(3x^2 - 11x + 6) = 1

4x - 5 = 3x^2 - 11x + 6

3x^2 - 15x + 11 = 0

By using Sridharacharya,

a = 3, b = -15, c = 11

x = [-b +- under root (b^2 - 4ac)]/2a

x = [15 +- under root (-15^2 - 4 × 3 × 11)]/2 × 3

x = [15 +- under root (225 - 132)]/6

x = [15 +- under root(93)]/6

Similar questions