Solve; 1/a+b+x=1/a+1/b+1/x
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1/(a+b+x)=1/a+1/b+1/x
=>1/(a+b+x)-1/a=1/b+1/x
=>(a-a-b-x)/(a+b+x)*a=(b+x)/bx
=>-(b+x)/(a.a+a.b+a.x)-(b+x)/bx=0
=>-(b+x)*(b.x+a.a+a.b+a.x)/(........)=0
=>(b+x)(x(a+b)+a(a+b))=0
=>(b+x)(a+x)(a+b)=0
=>(b+x)(a+x)=0
x= -a,-b
=>1/(a+b+x)-1/a=1/b+1/x
=>(a-a-b-x)/(a+b+x)*a=(b+x)/bx
=>-(b+x)/(a.a+a.b+a.x)-(b+x)/bx=0
=>-(b+x)*(b.x+a.a+a.b+a.x)/(........)=0
=>(b+x)(x(a+b)+a(a+b))=0
=>(b+x)(a+x)(a+b)=0
=>(b+x)(a+x)=0
x= -a,-b
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