Chemistry, asked by Mayuri1546, 3 months ago

Solve!!
1/(a+b+x) = 1/a + 1/b + 1/x
[x ≠ 0, x ≠ -(a+b)]​

Answers

Answered by lingamnagamani45
1

Answer:

)4515y455 \div 3920 =  =  |2502 \sqrt[5]{?} |

Answered by Yoursenorita
27

NOTE:-

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EXTRA INFORMATION:-

  • A quadratic equation is an equation of the following form: ax2+bx+c=0 where x represents an unknown variable, a, b, and c are constants, and a≠0. ... Because the term ax2 is raised to the second degree, it is called the quadratic term. The bx term is the linear term because it has a degree of 1.

  • The c term is the constant term because it has a degree of 0. Quadratic equations can be rearranged to be equal to 0. Zeros or roots of a quadratic are known as the solutions to quadratic equations a, b, and c don't have to be integers, so you can have a decimal as a constant! Therefore, it may initially seem like you need a perfect square, but you actually don't.

  • a, b, and c don't have to be integers, so you can have a decimal as a constant! Therefore, it may initially seem like you need a perfect square, but you actually don't.Quadratics can be solved by factorization, completing the square, or using the quadratic formula. To figure out how many solutions a quadratic has, you use the discriminant!

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