Math, asked by mareeswaran7576, 9 months ago

Solve 1/a²b-1/ab²≠0
=(A²-b²)/ab²-(a²-b²)/a²b
= ?

Answers

Answered by fab13
0

Answer:

 \frac{1}{ {a}^{2}b }  -  \frac{1}{ab {}^{2}  }

is not equal to 0

 \frac{ {a}^{2}  -  {b}^{2} }{a {b}^{2} } -   \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2} b}  \\  =  \frac{a( {a}^{2} -  {b}^{2}) - b( {a}^{2}   -   {b}^{2}) }{a {}^{2} b {}^{2}}  \\  =  \frac{( {a}^{2} -  {b}^{2})(a - b)  }{ {a}^{2} {b}^{2}  }  \\  =  \frac{ {a}^{3}  - a {b}^{2} -  {a}^{2} b +  {b}^{3}  }{ {a}^{2} {b}^{2}  }

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