solve 1 + cos ( x - y )
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Given, 1+cos(x−y)=0⇒1+2cos2(2x−y)−1=0
cos(2x−y)=0⇒(2x−y)=2π⇒x−y=π
⇒x=π+y
Taking cos both sides on x=π+y
cosx=cos(π+y)=−cosy⇒cosx+cosy=0
Taking sin both sides on x=π+y
sinx=sin(π+y)=−siny⇒sinx+siny=0
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