SOLVE: 1) DIVIDE 72 INTO TWO PARTS SO THAT THE LARGER PART EXCEEDS THE SMALLER PART BY 12. FIND BOTH THE PARTS.
sherinmohan:
PLEASE GIVE THE ANSWER
let 1st part be x,2nd part be 72-x. there4 x=72-x+12..then 2 parts will b 30,42
Answers
Answered by
10
let smaller part= x
larger part= 72-x
by hypothesis, we have
72-x-x=12
-2x+72-12=0
-2x+60=0
-2x=-60
x=30
smaller part=30
larger part=72-30=42
larger part= 72-x
by hypothesis, we have
72-x-x=12
-2x+72-12=0
-2x+60=0
-2x=-60
x=30
smaller part=30
larger part=72-30=42
Answered by
20
Let the first part be x and second part be x+12
according to the question
x + x + 12 = 72
2x + 12 = 72
2x = 72-12
2x = 60
x = 30
so first part = x = 30
second part = x + 12 = 30 + 12 = 42
according to the question
x + x + 12 = 72
2x + 12 = 72
2x = 72-12
2x = 60
x = 30
so first part = x = 30
second part = x + 12 = 30 + 12 = 42
Similar questions