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1. If x= 4/3 is a zero of the polynomial
p(x)=6x³-11x²+kx-20 then find "k"
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Answered by
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x=4/3
p(x)=6x³-11x²+kx-20
p(4/3)=6(4/3)³-11(4/3)²+k(4/3)-20
6(64/27)-11(16/9)+4k/3-20=0
2(64/9)-176/9+4k/3-20=0
128/9-176/9+4k/3-20=0
(128-176+12k-180)/9=0
(12k-228)/9=0
12k-228=0×9
12k=228
k=228/12
k=19
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