Math, asked by huxbchckch, 15 days ago

Solve 1 or 2



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Answered by Sirat4
1

Answer:

i) -4g⁴ + 12g³ - 9g² + 4g + 5

ii) 9a²/4 + 4b²/9  + 2ab

Step-by-step explanation:

i) -4g⁴ + 8g³ - 4g² - 2g + 11 - (3g² - 4g³ + 2g² - 6g + 6)

-4g⁴ + 8g³ - 4g² - 2g + 11 - 3g² + 4g³ - 2g² + 6g - 6

-4g⁴ + 12g³ - 9g² + 4g + 5

ii) (3/2a + 2/3b)²

sol. (3/2a)² + (2/3b)² + 2(3/2a)(2/3b)

  = 9a²/4 + 4b²/9  + 2ab

Answered by Anonymous
1

Step-by-step explanation:

(3a/2+2b/3)^2

by, (a+b)^2= a^2+b^2+2ab,

(3a/2)^2+(2b/3)^2+2*3a/2*2b/3

= 9a^2/4 + 4b^2/9 + 12ab/6

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