Question

Solve

1. p (8-2)=12
2. -5 (z+2)=-4
3. 6(k-3)=8​

Answer 1

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$1. : p(8 - 2) = 12$

$\therefore p(6) = 12$

$\therefore p = 12 \div 6$

$\green \Longrightarrow \blue{\fbox{p = 2}}$

2. \: ( - 5)(z + 2) = - 4 [/tex]

$\therefore - 5z - 10 = - 4$

$\therefore - 5z = - 4 + 10$

$\therefore - 5z = 6$

$\green \Longrightarrow \blue{ \boxed{ z = - \frac{6}{5} }}$

$3. \: 6(k - 3) = 8$

$\therefore 6k - 18 = 8$

$\therefore 6k = 8 - 18$

$\therefore 6k = - 10$

$\therefore k = - \frac{10}{6}$

$\green \Longrightarrow \blue{ \boxed{ k = - \frac{5}{3} }}$

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